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Reynolds Number & Flow Regimes — Reference

The ratio of inertial to viscous forces — the single number that decides whether flow is laminar or turbulent, and therefore which friction relation applies.

Definition

Re = ρVL/μ = VL/ν   (ν = μ/ρ)

Characteristic length L: pipe → diameter D (full-flow); open channel → hydraulic radius R = A/P. (Some texts use 4R for channels to align with the pipe definition — check which convention a threshold assumes.)

Flow Regime Thresholds

SystemLaminarTransitionalTurbulent
Pipe flow (L = D)< 21002100–4000> 4000
Open channel (L = R)< 500500–2000> 2000
Flow around a sphere/particle< 11–1000> 1000
Working a whole conveyance system? HydroComplete tracks the flow regime through every reach as the design storm passes.

Kinematic Viscosity of Water

Tempν (m²/s)ν (ft²/s)
5°C / 41°F1.52×10−61.63×10−5
10°C / 50°F1.31×10−61.41×10−5
20°C / 68°F1.00×10−61.08×10−5
30°C / 86°F0.80×10−60.86×10−5

Need density, specific weight or vapor pressure too? See the full water properties table (0–100°C / 32–212°F).

Why it matters. In laminar pipe flow the friction factor is simply f = 64/Re (roughness irrelevant). In turbulent flow you need Colebrook / Swamee-Jain with the relative roughness. The Froude number (not Reynolds) governs the sub/supercritical state of open-channel flow — Reynolds only tells you it's turbulent, which it nearly always is.

Sources: White, F.M., Fluid Mechanics. Munson et al., Fundamentals of Fluid Mechanics. Viscosity values: standard water property tables.

Checking a flow regime? Open the Reynolds calculator → · Turbulent friction? Roughness & friction factor. · Want the whole set? Print all 38 cards →

Worked examples: one turbulent, one laminar

12-in pipe, Q = 1.5 cfs, water at 50°F (ν = 1.41×10⁻⁵ ft²/s)

Find flow regime and which friction relation to use
V = Q/A = 1.5 / (π × 1²/4) = 1.91 ft/s
Re = V·D/ν = 1.91 × 1.0 / 1.41×10⁻⁵ = 135,000 → fully turbulent
Use Colebrook or Swamee-Jain with the pipe’s relative roughness ε/D

1-in drain line, V = 0.1 ft/s, same water

Find flow regime and friction factor
Re = 0.1 × (1/12) / 1.41×10⁻⁵ = 591 → laminar
f = 64/Re = 64/591 = 0.108, and roughness does not matter
Colebrook and Swamee-Jain are not valid at this Reynolds number, so their answer here would simply be wrong

The first case is typical: water in civil infrastructure is almost always turbulent, so the Reynolds number mainly tells you to use a turbulent friction relation. The second case is where the check matters. Small, slow flows include drain lines, chemical feed tubing, and seepage through a filter or sand bed. In those, laminar flow is real, and the turbulent friction relations do not apply.

Common mistakes

When this card doesn’t apply

The thresholds are for Newtonian fluids in steady, fully developed flow. Sludges, slurries and drilling muds are non-Newtonian and need a rheological model and a modified Reynolds number. Flow through porous media uses a particle-diameter Reynolds number. In that case Darcy’s law holds only below Re of roughly 1–10. Entrance regions, pulsating flow and flow with heat transfer transition at different values.

Related cheat sheets and tools

Confirm the regime with the Reynolds tool, then pick the friction relation from the roughness card and compute loss in Darcy-Weisbach. For open channels, the specific-energy card covers the Froude side. For full network modeling, see HydroComplete.

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