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Reynolds Number Calculator

Compute Re for a pipe or open-channel flow and read the regime: laminar, transitional, or turbulent.

ft/s
ft
ft²/s
——
——

Defaults are water at 60°F (ν = 1.21 × 10⁻⁵ ft²/s) in a 6-inch pipe at 5 ft/s.

$$ Re = \frac{V L}{\nu} $$
V mean velocity · L characteristic length (= pipe diameter D, or hydraulic radius Rh for open channel) · ν kinematic viscosity of fluid.

Regime thresholds — by geometry

Reynolds-number boundaries between flow regimes for common configurations
GeometryLaminarTransitionalTurbulent
Round pipe (internal flow)< 2,3002,300–4,000> 4,000
Non-circular duct (use Dh)< 2,3002,300–4,000> 4,000
Open channel (use Rh)< 500500–2,000> 2,000
Flat plate boundary layer< 5×10⁵5×10⁵> 5×10⁵
Sphere drag (transition to wake)< 11–10⁵> 10⁵
Cylinder cross-flow (vortex shed.)< 4040–10⁵> 3×10⁵

The open-channel limits look lower only because they are written with L = Rh. For a full pipe Rh = D/4, so 500 and 2,000 on an Rh basis correspond to 2,000 and 8,000 on a diameter basis. Engineering practice usually treats pipe flow above Re = 2,300 as effectively turbulent and uses rough-pipe friction formulas conservatively in the transitional band.

Kinematic viscosity ν of common fluids

Kinematic viscosity at typical engineering temperatures
Fluid / temperatureν (US ft²/s)ν (SI m²/s)
Water, 32°F (0°C)1.92×10⁻⁵1.79×10⁻⁶
Water, 40°F (4°C)1.66×10⁻⁵1.55×10⁻⁶
Water, 50°F (10°C)1.41×10⁻⁵1.31×10⁻⁶
Water, 60°F (16°C)1.21×10⁻⁵1.13×10⁻⁶
Water, 70°F (21°C)1.06×10⁻⁵9.84×10⁻⁷
Water, 80°F (27°C)9.30×10⁻⁶8.64×10⁻⁷
Water, 100°F (38°C)7.39×10⁻⁶6.87×10⁻⁷
Air, 60°F1.58×10⁻⁴1.47×10⁻⁵
SAE 10W oil, 60°F1.0×10⁻³9.3×10⁻⁵
SAE 30 oil, 60°F4.1×10⁻³3.8×10⁻⁴
Glycerin, 70°F6.5×10⁻³6.0×10⁻⁴
Mercury, 60°F1.21×10⁻⁶1.13×10⁻⁷

Worked examples

Example 1 — 6-inch water main at 5 ft/s

Given: 6-inch (D = 0.5 ft) pipe, V = 5 ft/s, water at 60°F (ν = 1.21×10⁻⁵ ft²/s).
Find: Reynolds number and regime.
Re = V·D/ν = 5·0.5/(1.21×10⁻⁵)
Re = 2.07×10⁵
Re ≈ 207,000 — fully turbulent. Use Swamee-Jain for friction factor.

Example 2 — Hydraulic-oil cooler line, small diameter

Given: ½-inch line, V = 2 ft/s, SAE 30 oil at 60°F (ν = 4.1×10⁻³ ft²/s).
Find: Re and regime.
D = 0.5/12 = 0.0417 ft
Re = 2·0.0417/(4.1×10⁻³) = 0.0833/0.0041 = 20.3
Re = 20 — strongly laminar. Use f = 64/Re = 3.15 in Darcy-Weisbach.

Reference: White, F.M. (2011). Fluid Mechanics (7th ed.). McGraw-Hill. Original concept: Reynolds, O. (1883). "An experimental investigation of the circumstances which determine whether the motion of water shall be direct or sinuous." Phil. Trans. Royal Soc. London, 174, 935–982.

Common mistakes

When this calculator doesn’t apply

The thresholds are for steady, fully developed flow of a Newtonian fluid. Flow just downstream of an entrance or fitting, pulsating flow and heated pipes transition at different values. Sludges, slurries and polymer solutions are non-Newtonian and need a generalized Reynolds number. Flow through soil or filter media uses a particle-based Reynolds number, and Darcy’s law is valid only at low values of it.

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