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Truss Member Force Coefficients — Reference

Maximum member forces as a multiple of the total uniform gravity load W on the truss. Multiply by W = pressure × spacing × span. Positive = tension, − = compression.

Fmember = C × W     W = w (psf) × s (ft) × L (ft)

Pitched roof trusses — load on the top chord

TrussPitchTop chord
max C
Bottom chord
max T
Web
max T
Web
max C
King post4/12−0.7910.75000
6/12−0.5590.50000
8/12−0.4510.37500
12/12−0.3540.25000
Queen post4/12−1.0541.0000.354−0.250
6/12−0.7450.6670.300−0.250
8/12−0.6010.5000.280−0.250
12/12−0.4710.3330.264−0.250
Fink (W)4/12−1.1861.1250.265−0.265
6/12−0.8390.7500.225−0.225
8/12−0.6760.5620.210−0.210
12/12−0.5300.3750.198−0.198
Howe roof
6 panels
4/12−1.3181.2500.354−0.250
6/12−0.9320.8330.300−0.250
8/12−0.7510.6250.280−0.250
12/12−0.5890.4170.264−0.250
Pratt roof
6 panels
4/12−1.3181.2500.333−0.300
6/12−0.9320.8330.333−0.236
8/12−0.7510.6250.333−0.208
12/12−0.5890.4170.333−0.186
Scissor
bottom pitch = ½ top
4/12−2.3722.2810.839−0.250
6/12−1.6771.5460.625−0.250
8/12−1.3521.1860.530−0.250
12/12−1.0610.8390.500−0.250

Load W is applied uniformly on plan along the top chord and lumped at the top panel points; the half-panels at the heels go directly to the supports. King post: one top joint (apex). Queen post: top joints at the third points. Fink: top joints at the quarter points, bottom joints at the third points.

Parallel-chord trusses — 6 panels, load on the top chord

TrussDepthTop chord
max C
Bottom chord
max T
Web
max T
Web
max C
PrattL/8−1.0000.8890.694−0.500
L/10−1.2501.1110.810−0.500
L/12−1.5001.3330.932−0.500
HoweL/8−0.8891.0000.250−0.694
L/10−1.1111.2500.250−0.810
L/12−1.3331.5000.250−0.932
WarrenL/8−1.0001.0000.401−0.601
L/10−1.2501.2500.434−0.651
L/12−1.5001.5000.471−0.707
Warren + verticalsL/8−0.8891.0000.417−0.694
L/10−1.1111.2500.486−0.810
L/12−1.3331.5000.559−0.932

Load W/6 at each interior top panel point and W/12 at each end top joint; supports at the bottom-chord ends. Pratt: max web compression is the end vertical (the full reaction W/2). Howe: max web compression is the end diagonal.

Quick checks. Chord force at midspan ≈ M / d = (WL/8) / d, so a flat truss with depth L/8 has a chord force of about 1.0 W, and one with depth L/12 about 1.5 W. For a pitched truss, the bottom-chord force at the heel is (R − heel load) / tanθ: lower pitch, bigger force.

What the coefficients leave out

EffectWhat to do
Ceiling load on the bottom chordAdd it as a second case; it changes the web forces and adds bending to the bottom chord
Chord bending between panel pointsCombine axial force with panel bending (NDS Eq. 3.9-1 / 3.9-3); it often governs the top chord
Unbalanced or drift snow, point loadsAnalyze the actual loading; webs near midspan can reverse
Wind upliftEvery force reverses under net uplift; check members that were in tension for buckling

Coefficients computed by PE-Calc with the stiffness solver in the truss calculator (pin-jointed, linear elastic) and checked against the method of joints; determinate trusses, so independent of member size. Spans and panel layouts as stated; values are rounded to three decimals.

Your truss, your loads, NDS or AISC checks: Truss calculator → · Worked example: Fink roof truss · Want the whole set? Print all the cards →

Related cheat sheets and tools

Pair with the unit weights card for dead loads, the Euler buckling tool for compression members, and 3D frame analysis when the truss is part of a frame.

Frequently asked questions

How do I use truss force coefficients?

Multiply the coefficient by the total uniform load on the truss, W = pressure × spacing × span (for example 30 psf × 2 ft × 28 ft = 1,680 lb). A Fink truss at 6/12 has a top-chord coefficient of −0.839, so the maximum top-chord compression is 0.839 × 1,680 = 1,410 lb. Negative values are compression.

Why does a lower pitch increase truss forces?

The chords resist the bending moment of the whole truss as a couple, and the lever arm is the truss rise. Halving the pitch roughly halves the rise and doubles the chord forces. A king post truss at 4/12 has 1.5 times the bottom-chord force of the same truss at 6/12.

Which web carries the most compression in a flat Pratt truss?

The end vertical over each support carries the whole reaction, W/2, in compression. The interior verticals carry less, and the diagonals are in tension. In a Howe truss, the pattern reverses: the end diagonals carry the largest compression and the verticals are in tension.

Are these coefficients accurate enough for design?

They are exact for the stated geometry and loading, a pin-jointed truss under uniform gravity load at the panel points. They are not a substitute for an analysis with the actual loads (ceiling load on the bottom chord, unbalanced snow, point loads, uplift), the bending of loaded chords, and the member checks. Use them for preliminary sizing and to check software output.

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