Breach Parameters for a 22-ft Earthfill Dam
Froehlich (2008) average breach width and failure time, and the Froehlich (1995) peak discharge regression, worked end to end in SI and reported in customary units — the numbers that feed an inundation map, and the ones a reviewer will check first. Sources: Froehlich, D.C. (2008), Embankment Dam Breach Parameters and Their Uncertainties, ASCE J. Hydraulic Engineering; Froehlich (1995a), Embankment Dam Breach Parameters Revisited.
The structure
| Type | Homogeneous earthfill embankment, recreation impoundment |
| Dam height | 22 ft |
| Normal storage | 145 acre-ft |
| Breach height, hb | 20 ft (breach cuts to near original ground) |
| Depth of water above breach invert, hw | 20 ft at the moment of failure |
| Failure mode | Overtopping (also run as piping for comparison) |
The Froehlich regressions are metric
Both Froehlich sets are fitted in SI. Converting first and reporting back out is safer than hunting for a customary-unit restatement, which is where most spreadsheet errors in this calculation come from.
hb = 20 ft × 0.3048 = 6.096 m
hw = 20 ft × 0.3048 = 6.096 m
Why this matters more than it looks: check the dimensions of each equation before you trust it in any unit system.
| Equation | Length dimension | Homogeneous? | Consequence |
|---|---|---|---|
| B̄ = 0.27·Ko·Vw0.32·hb0.04 | L3(0.32)+0.04 = L1.00 | Yes | Unit-invariant — works in ft or m |
| tf = 63.2√(Vw/(g·hb²)) | √(L³/L³T−2) = T | Yes | Unit-invariant, with g in matching units |
| Qp = 0.607·Vw0.295·hw1.24 | L3(0.295)+1.24 = L2.125 | No — Q needs L³T−1 | SI only |
Froehlich (2008): B̄ = 0.27·Ko·Vw0.32·hb0.04
Vw0.32 = 178,8550.32 = 47.95
hb0.04 = 6.0960.04 = 1.0750
Overtopping: B̄ = 0.27 × 1.3 × 47.95 × 1.0750 = 18.09 m = 59.4 ft
Piping: B̄ = 0.27 × 1.0 × 47.95 × 1.0750 = 13.92 m = 45.7 ft
Note how weakly breach width depends on breach height: the exponent on hb is 0.04, so doubling the breach height moves the width by under 3%. Storage volume, at exponent 0.32, does essentially all the work. Getting the stage-storage curve right matters far more than refining the breach elevation.
tf = 63.2·√(Vw / (g·hb²))
Vw / (g·hb²) = 178,855 / 364.6 = 490.5
√490.5 = 22.15
tf = 63.2 × 22.15 = 1,400 s = 0.39 hr ≈ 23 minutes
Froehlich (1995): Qp = 0.607·Vw0.295·hw1.24
hw1.24 = 6.0961.24 = 9.407
Qp = 0.607 × 35.44 × 9.407 = 202.4 m³/s = 7,150 cfs
For scale: this 22-foot recreation dam releases roughly seven thousand cubic feet per second at the breach — comparable to a substantial river in flood, out of a pond most neighbours would call small. This is the single most useful number for explaining to an owner why their dam is regulated.
What goes on the calc sheet
| Parameter | Overtopping | Piping | Source |
|---|---|---|---|
| Average breach width B̄ | 59.4 ft | 45.7 ft | Froehlich 2008 |
| Side slopes (H:V) | 1.0:1 | 0.7:1 | Froehlich 2008 |
| Failure time tf | 0.39 hr | 0.39 hr | Froehlich 2008 |
| Peak discharge Qp | 7,150 cfs | 7,150 cfs | Froehlich 1995 |
Tools used
The rest of this series
These four examples follow one structure through the whole decision chain, because in practice that is how the questions actually arrive:
- Breach parameters for a 22-ft earthfill dam — produces the failure hydrograph everything else depends on.
- Class B or Class C? The 1.5-foot flood rise test — turns that hydrograph into a hazard classification.
- Does an 18-ft farm pond dam need a permit? — the classification decides whether the size exemption survives.
- Spillway design flood for a Class C dam — and the classification sets the storm the spillway must pass.